[osm] In the case of semicolon delimited names, choose one at random
This commit is contained in:
@@ -445,6 +445,9 @@ class OSMAddressFormatter(object):
|
||||
language_suffix = ''
|
||||
|
||||
if name and name.strip():
|
||||
if six.u(';') in name:
|
||||
name = random.choice(name.split(six.u(';')))
|
||||
|
||||
for i in xrange(num_references if name_tag == 'name' else 1):
|
||||
address_components = {component_name: name.strip()}
|
||||
self.components.add_admin_boundaries(address_components, osm_components, country, UNKNOWN_LANGUAGE,
|
||||
@@ -465,6 +468,9 @@ class OSMAddressFormatter(object):
|
||||
if not name or not name.strip():
|
||||
continue
|
||||
|
||||
if six.u(';') in name:
|
||||
name = random.choice(name.split(six.u(';')))
|
||||
|
||||
for i in xrange(num_references if is_default and name_tag == 'name' else 1):
|
||||
address_components = {component_name: name.strip()}
|
||||
self.components.add_admin_boundaries(address_components, osm_components, country, language,
|
||||
@@ -484,6 +490,9 @@ class OSMAddressFormatter(object):
|
||||
if not name or not name.strip():
|
||||
continue
|
||||
|
||||
if six.u(';') in name:
|
||||
name = random.choice(name.split(six.u(';')))
|
||||
|
||||
address_components = {component_name: name.strip()}
|
||||
self.components.add_admin_boundaries(address_components, osm_components, country, language,
|
||||
random_key=False,
|
||||
|
||||
Reference in New Issue
Block a user