[intersections] Better handling of default languages in intersection queries
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@@ -1087,6 +1087,8 @@ class OSMAddressFormatter(object):
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if not (country and candidate_languages):
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continue
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more_than_one_official_language = sum((1 for l in candidate_languages if int(l['default']))) > 1
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base_name_tag = None
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for t in all_base_name_tags:
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if any((t in way for way in ways)):
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@@ -1099,6 +1101,18 @@ class OSMAddressFormatter(object):
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for way in ways:
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names = defaultdict(list)
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if len(candidate_languages) == 1:
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default_language = candidate_languages[0][0]
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elif not more_than_one_official_language:
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default_language = None
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name = way['name']
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if not name:
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continue
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address_language = self.components.address_language({AddressFormatter.ROAD: name}, candidate_languages)
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if address_language and address_language not in (UNKNOWN_LANGUAGE, AMBIGUOUS_LANGUAGE):
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default_language = address_language
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for tag in way:
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tag = safe_decode(tag)
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base_tag = tag.rsplit(six.u(':'), 1)[0]
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@@ -1111,8 +1125,10 @@ class OSMAddressFormatter(object):
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lang = safe_decode(tag.rsplit(six.u(':'))[-1]) if six.u(':') in tag else None
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if lang and lang.lower() in all_languages:
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lang = lang.lower()
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elif default_language:
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lang = default_language
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else:
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lang = None
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continue
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namespaced_languages.add(lang)
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@@ -1124,8 +1140,8 @@ class OSMAddressFormatter(object):
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names[lang].append(way[tag])
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if base_name_tag in way:
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names[None].append(way[base_name_tag])
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if base_name_tag in way and default_language:
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names[default_language].append(way[base_name_tag])
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if not names:
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continue
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