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[osm/addresses] Factoring out semicolon/comma-delimited name cleanup into its own method

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Al
2016-08-17 18:45:33 -04:00
parent 145af9331e
commit 7b314324ca
1 changed files with 22 additions and 8 deletions
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30
scripts/geodata/addresses/components.py
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@@ -722,10 +722,7 @@ class AddressComponents(object):
name = boundary_names.name(country, name)
if name and not (name == existing_city_name and component != AddressFormatter.CITY and drop_duplicate_city_names):
if six.u(';') in name:
name = random.choice(name.split(six.u(';'))).strip()
elif six.u(',') in name:
name = name.split(six.u(','), 1)[0].strip()
name = self.cleaned_name(name, first_comma_delimited_phrase=True)
break
# if we've checked all keys without finding a valid name, leave this component out
else:
@@ -1048,6 +1045,23 @@ class AddressComponents(object):
for component in components[1:]:
address_components.pop(component, None)
def cleaned_name(self, name, first_comma_delimited_phrase=False):
'''
General name cleanup
--------------------
Names in OSM and other tagged data sets may contain more than a single
field. If the field is separated by semicolons, split it and pick one
of the subfields at random (common in street names). If first_comma_delimited_phrase
is True, and the phrase has a comma in it, return only the portion of the string
before the comma.
'''
if six.u(';') in name:
name = random.choice(name.split(six.u(';'))).strip()
elif first_comma_delimited_phrase and six.u(',') in name:
name = name.split(six.u(','), 1)[0].strip()
return name
def cleanup_venue_name(self, address_components):
'''
Venue name cleanup
@@ -1081,11 +1095,11 @@ class AddressComponents(object):
house_number = address_components.get(AddressFormatter.HOUSE_NUMBER)
if not house_number:
return
if ';' in house_number:
house_number = house_number.replace(';', ',')
if six.u(';') in house_number:
house_number = house_number.replace(six.u(';'), six.u(','))
address_components[AddressFormatter.HOUSE_NUMBER] = house_number
if house_number and house_number.count(',') >= 2:
house_numbers = house_number.split(',')
if house_number and house_number.count(six.u(',')) >= 2:
house_numbers = house_number.split(six.u(','))
random.shuffle(house_numbers)
for num in house_numbers:
num = num.strip()